The system shown in the diagram consists of two flat conducting strips of length λ , width b (perpendicular to plane of diagram) separated by a small gap 'a' (where a <<< b, λ ). The right ends of the strips are shorted and a battery of voltage V 0 is connected across the left ends. The current is assumed to flow only parallel to the λ -dimension of the strips. Neglect all resistances.
(i) What is the self inductance of the circuit–
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Ans.
(i)
Sol.
Flux = B × Area
= μ 0 J × λ × a
φ = 
φ = Li
L = 
= 
(ii) ( a)
Sol. V x = 
Using kirchoff 's law
V 0 – 
= 0
i = 
L 1 = 
V x = 
× 
= 
(iii)
Sol. Energy flow rate = V x × i
= 
= 
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